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// table的id  需要合并的列（從0開始算）

    mergeCell(tableId, cols) {

      const table = document.getElementById(tableId);

      if (!table)return

      const table_rows = table.rows;

      // 需要合并的列的數組

      cols.forEach((v, k) => {

        // 循環table每一行

        for (let i = 0; i < table_rows.length - 1; i++) {

          // row

          let now_row = table_rows[i];

          let next_row = table_rows[i + 1];

          // col

          let now_col = now_row.cells[v];

          let next_col = next_row.cells[v];

          if (now_col.innerHTML == next_col.innerHTML) {

            // 標記為需要刪除

            next_col.classList.add('remove');

            // 遞歸判斷當前對象時候已經被刪除

            this.setParentSpan(table, i, v);

          }

        }

      })

      let removeTds = document.getElementsByClassName('remove');

      for (let i = removeTds.length-1; i >= 0; i--) {

        let eldTd = removeTds[i];

        eldTd.parentNode.removeChild(eldTd);

      }

    }

    setParentSpan(table, row, col) {

      const col_item = table.rows[row].cells[col];

      if (col_item.classList.contains('remove')) {

        this.setParentSpan(table, --row, col)

      } else {

        col_item.rowSpan += 1;

      }

    }

// 使用，合并id為table1的第一列數據，相同的合并

mergeCell("table1", [0])